by Trust » Thu Nov 03, 2005 4:49 pm
Hi Stan!
Below is a example of statistics of announcers with draws from
the Expertlotto 6/49 - copied from Exp.lotto statistics
As i understand it the standard way to count the total occasions of
trailing numbers is to count each occurence of announcing number
with each of the following numbers.
Example:Assume we shall find the total occurences of trailing number
12 :Take the first num in latest draw(6) and find all occurences of 6
followed by 12=(1),13 is followed by 12 twice(2),14 followed by 12
(1),19 followed by 12 (3),41 and 42=(0) -this sums up to 7 occurences
of trailing num 12 in this period.
Total occurences of Trnum 23 should be 6.(I have not counted up
the rest of the numbers)
The way the statistics of occurences is calculated in Exp.lotto now is to count each occurence of any announcing number.
I hope you understand the differences in this methods.
TrNum Occ Draws
12 5 2004,28,2,1,6,13,14,19,41,42,29
23 5 2004,28,2,2,23,29,36,42,44,47,7
30 4 2004,28,1,1,16,18,22,23,28,29,24
33 4 2004,28,1,2,2,13,16,17,25,40,27
1 3 2004,27,2,1,2,15,22,29,30,37,42
3 3 2004,27,2,2,1,6,12,24,32,41,44
13 3 2004,27,1,1,8,11,19,26,48,49,18
19 3 2004,27,1,2,20,23,25,30,33,35,7
25 3 2004,26,2,1,5,6,11,31,40,43,32
27 3 2004,26,2,2,8,11,18,32,36,38,6
29 3 2004,26,1,1,5,12,25,31,44,46,33
32 3 2004,26,1,2,4,18,26,33,35,47,11
41 3 2004,25,2,1,16,21,24,25,35,46,47
48 3 2004,25,2,2,10,15,28,30,36,43,35
2 2 2004,25,1,1,1,6,22,24,34,40,33
6 2 2004,25,1,2,9,12,23,34,39,49,24
14 2 2004,24,2,1,11,19,28,29,32,39,30
15 2 2004,24,2,2,8,12,23,31,37,49,27
20 2 2004,24,1,1,1,5,27,33,39,48,36
22 2 2004,24,1,2,12,25,27,33,35,41,20
24 2 2004,23,2,1,3,13,14,19,23,48,15
28 2 2004,23,2,2,1,12,24,33,38,42,11
2004,23,1,1,3,4,13,25,29,34,37
2004,23,1,2,2,19,20,23,32,48,24
2004,22,2,1,3,13,19,27,31,44,2
2004,22,2,2,4,7,8,23,25,28,31
2004,22,1,1,3,7,12,27,30,32,1
2004,22,1,2,3,5,6,18,20,22,48